Ответ:
дано
W(KOH) =4%
m(ppa HCL) = 40 g
W(HCL) = 30%
--------------------
m(ppa KOH)-?
m(HCL) = 40 * 30% / 100% = 12 g
KOH+HCL-->KCL+H2O
M(KOH) = 56 g/mol
M(HCL) = 36.5 g/mol
m(KOH) = 56*12 / 36.5 = 18.41 g
m(ppa KOH) = 18.41 * 100% / 4% = 460.25 g
ответ 460.25 г
Объяснение: