Даю 100 баллов только помогите 6.33

Решите задачу:

$1) \:\frac{ax-y}{a+b} +\frac{y+bx}{a+b} =\frac{ax-y+y+bx}{a+b} =\\=\frac{x(a+b)}{a+b} = x$

$2)\: \frac{n+mx}{m+3} -\frac{n-3x}{m+3} =\frac{n+mx-(n-3x)}{m+3}=\\ =\frac{x(m+3)}{m+3} = x$

$3)\: \frac{px-3q}{x-y}+\frac{py-3q}{y-x} = \frac{px-3q}{x-y}-\frac{py-3q}{x-y} =\\=\frac{px-3q-py+3q}{x-y} =\frac{p(x-y)}{x-y}=p$

$4) \:\frac{2cx+b}{2c-3} + \frac{3x+b}{3-2c} = \frac{2cx+b}{2c-3} - \frac{3x+b}{2c-3} =\\= \frac{2cx+b-3x-b}{2c-3}=\frac{x(2c-3)}{2c-3} = x$