Ответ:
Ответ смотрите также во Вложении.
Объяснение:
x-4(3x+1)} \atop {20-x \geq (1+9x)^2 -81x^2}} \right.\\\\\left \{ {{-3x>x-12x-4} \atop {20-x \geq (1+9x-9x)(1+9x+9x)}} \right. \\\\ \left \{ {{-3x>-11x-4} \atop {20-x \geq 18x + 1} \right.\\\\ \left \{ {{-3x+11x>-4} \atop {-x -18x \geq 1 - 20} \right.\\\\ \left \{ {{8x>-4} \atop {-19x \geq - 19} \right. \\\\ \left \{ {{x>-0,5} \atop {x\leq1}} \right. \\\\ x\in (-0,5; 1]\\\\x = 0; 1" alt="\left \{ {{-3x>x-4(3x+1)} \atop {20-x \geq (1+9x)^2 -81x^2}} \right.\\\\\left \{ {{-3x>x-12x-4} \atop {20-x \geq (1+9x-9x)(1+9x+9x)}} \right. \\\\ \left \{ {{-3x>-11x-4} \atop {20-x \geq 18x + 1} \right.\\\\ \left \{ {{-3x+11x>-4} \atop {-x -18x \geq 1 - 20} \right.\\\\ \left \{ {{8x>-4} \atop {-19x \geq - 19} \right. \\\\ \left \{ {{x>-0,5} \atop {x\leq1}} \right. \\\\ x\in (-0,5; 1]\\\\x = 0; 1" align="absmiddle" class="latex-formula">
