Реши систему уравнений:5y + 4х = 514х— 3y = 0

Ответ:

( x, y ) = ( $\frac{15}{82}$ , $\frac{35}{41}$ )

Объяснение:

$\left \{ {{5y + 4x = 5} \atop {14x - 3y = 0}} \right.$

y = 1 - $\frac{4}{5}$ x

14x - 3(1 - $\frac{4}{5}$ x) = 0

14x - 3 + $\frac{12}{5}$ x = 0

$\frac{82}{5}$ x - 3 = 0

82x - 15 = 0

82x = 15

x = $\frac{15}{82}$

y = 1 - $\frac{4}{5}$ * $\frac{15}{82}$

y = $\frac{35}{41}$

( x, y ) = ( $\frac{15}{82}$ , $\frac{35}{41}$ )

Реши систему уравнений:5y + 4х = 514х— 3y = 0​