Паскаль 3*7 div 2 mod 7 int (35.7) frac (35.7) round (35.7) sqr(3)+round (6.8)

Question

Паскаль 3*7 div 2 mod 7 int (35.7) frac (35.7) round (35.7) sqr(3)+round (6.8)

Answer 1

Ответ:

3*7 div 2 mod 7 = 3

int (35.7) = 35

frac (35.7) = 0.700000000000003

round (35.7) = 36

sqr(3)+round (6.8) = 16