Помогите пожалуйста решить эти задания!!!!!!!!!

1)3i - (24 + 15i) = 3i - 24 - 15i = - 12i - 24

2) (2i + 3) + (12 - 3i) = 2i + 3 + 12 - 3i = 15 - i

3) (17 - 3i)(17 + 3i) = 17² - (3i)² = 289 - 9i² = 289 + 9 = 298

$4)\frac{3+5i}{4i+2}=\frac{(3+5i)(4i-2)}{(4i+2)(4i-2)}=\frac{12i-6+20i^{2}-10i}{16i^{2}-4}=\frac{2i-6-20}{-16-4}=\frac{2i-26}{-20}=\frac{13-i}{10}\\\\5)9ix+6=-11x+5i\\\\9ix+11x=5i-6\\\\x(9i+11)=5i-6\\\\x=\frac{5i-6}{9i+11} =\frac{(5i-6)(9i-11)}{(9i+11)(9i-11)}=\frac{45i^{2}-55i-54i+66}{81i^{2}-121 }=\frac{-45-109i+66}{-81-121}=\frac{109i-21}{202}\\\\x=\frac{109i-21}{202}$