\sqrt{x} =5=>x=25 \\ 25=y=18 => y=9" alt=" \left \{ {{ \sqrt{x}+ \sqrt{y}=8 } \atop { x-y=16 }} \right. \\ \\ x-y=( \sqrt{x}+ \sqrt{y})( \sqrt{x}- \sqrt{y})=8( \sqrt{x}- \sqrt{y})=16 \\ \left \{ {{\sqrt{x}+ \sqrt{y}=8} \atop {\sqrt{x}- \sqrt{y}=2}} \right. \\ 2 \sqrt{x} =10 => \sqrt{x} =5=>x=25 \\ 25=y=18 => y=9" align="absmiddle" class="latex-formula">
Ответ: х=25
у=9