Помогите мне решить пожалуйста

Решение:

$1) 5(x-3)+2 = 3(x - 4) + 2x - 1\\\\5x - 15 + 2 = 3x - 12 + 2x - 1\\\\5x - 3x - 2x = -12 - 1 + 15 - 2\\\\0x = 0\\\\x\in R$

$2) 2(x + 3) = 5 - 6x\\\\2x + 6 = 5 - 6x\\\\2x + 6x = 5 - 6\\\\8x = -1\\\\x = -0,125$

$3) -6(5 - 3x) = 8x - 7\\\\-30 + 18x = 8x - 7\\\\18x - 8x = -7 + 30\\\\10x = 23\\\\x = 2,3$

Задание №10

$a) 15(x + 2) = 40\\\\15x + 30 = 40\\\\15x = 40 - 30\\\\15x = 10\\\\x = \frac{10}{15}\\\\x = \frac{2}{3}$

$b) -2(1 - x) = x\\\\-2 + 2x = x\\\\2x - x = 2\\\\x = 2$

$v) 5(2x + 1) = 3(2 - x)\\\\10x + 5 = 6 - 3x\\\\10x + 3x = 6 - 5\\\\13x = 1\\\\x = \frac{1}{13}$

$g) -6(2-x) = 5(1+x)\\\\-12+6x = 5 + 5x\\\\6x - 5x = 5 + 12\\\\x = 17$