ОЧЕНЬ СРОЧНО РЕШИТЬ УРАВНЕНИЯ

Ответ:

1)(х- $\frac{77}{12}$ )× $\frac{8}{5}$ =4

$\frac{8}{5}$ ×( $-\frac{154}{15}$ )=4

24х-154=6-

24х=6-+154

24х=124

х= $\frac{107}{12}$

2) $\frac{12}{19}$ ×( $\frac{9}{38}$ )= $\frac{1}{2}$

24х+9=19

24х+19-9

24х=10

х= $\frac{5}{12}$

3)х× $\frac{32}{9}$ × $\frac{15}{16}$ + $\frac{1}{2}$ =1

х× $\frac{2}{3}$ ×5+ $\frac{1}{2}$ =1

$\frac{10}{3}x$ + $\frac{1}{2}$ =1

20х+3=6

20х=6-3

20х=3

х= $\frac{3}{20}$

4) $\frac{39}{2}$ × $(\frac{5}{3} -x)=0$

$\frac{65}{2} -\frac{39}{2} x=0$

65-39х=0

-39х=-65

х= $\frac{5}{3}$

Пошаговое объяснение:

Решите задачу:

$1)\;\left(x-6\frac5{12}\right):\frac58=4\\\\x-6\frac5{12}=4\cdot\frac58\\\\x-\frac{77}{12}=\frac52\\\\x=\frac52+\frac{77}{12}=\frac{5\cdot6+77}{123}=\frac{30+77}{12}=\frac{107}{12}=8\frac{11}{12}$

$2)\;\left(x+\frac38\right)\cdot\frac{12}{19}=\frac12\\\\x+\frac38=\frac12\cdot\frac{19}{12}\\\\x+\frac38=\frac{19}{24}\\\\x=\frac{19}{24}-\frac38=\frac{19-3\cdot3}{24}=\frac{19-9}{24}=\frac{10}{24}=\frac5{12}$

$3)\;x:\frac9{32}\cdot\frac{15}{16}+\frac12=1\\\\x\cdot\frac{32}9\cdot\frac{15}{16}=\frac12\\\\x\cdot\frac23\cdot\frac51=\frac12\\\\x\cdot\frac{10}3=\frac12\\\\x=\frac12\cdot\frac3{10}=\frac3{20}$

$4)\;\frac23\cdot\left(\frac53-x\right)\cdot13=0\\\\\frac53-x=0\\\\x=\frac53$