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Решите задачу:

$\frac{1}{5} x - \frac{1}{3} ( 1\frac{1}{5} x - 27) = x + ( \frac{1}{2} x + 3) \\ \frac{1}{5} x - \frac{2}{5} x + 9 = x + \frac{1}{2} x + 3 | \times 10 | \\ 2x - 4x + 90 = 10x + 5x + 30 \\ - 17x = - 60 \\ x = \frac{60}{17} = 3\frac{9}{17}$

${x}^{8} - \frac{1}{49} {x}^{6} = 0 \\ {x}^{6} ( {x}^{2} - \frac{1}{49} ) = 0 \\ {x}^{6} = 0 \\ {x}^{2} - \frac{1}{49} = 0 \\ x1 = 0 \\ x2 = \frac{1}{7 } \\ x3 = - \frac{1}{7}$