Помогите плиз) оч прошу)

Решите задачу:

$\cfrac{18x^2y}{24xy^3}= \cfrac{3x}{4y^2}$

$\cfrac{6x-2x^2}{2x-6} = \cfrac{-x(2x-6)}{2x-6}=-x$

$\cfrac{4x^2-1}{1-4x+4x^2} = \cfrac{(2x-1)(2x+1)}{(2x-1)^2} = \cfrac{2x+1}{2x-1}$

$\cfrac{m^3+8n^3}{2n+m} = \cfrac{(m+2n)(m^2-2mn+4n^2)}{2n+m}=m^2-2mn+4n^2$

$\cfrac{2^{n+1}\cdot x-2^{n+2}}{2^n\cdot x^2-2^{n+2}} = \cfrac{2x-2^2}{x^2-2^2} = \cfrac{2(x-2)}{(x-2)(x+2)} = \cfrac{2}{x+2}$