Пожалуйста помогите срочно!!

а) $\frac{a+6}{a^{2}-36 } = \frac{a+6}{(a-6)(a+6) } = \frac{1}{a-6}$

б) $\frac{3x+27y}{9xy} = \frac{3(x+9y)}{3*3*xy} = \frac{x+9y}{3xy}$

в) $\frac{y^{2} }{y^{2}+5y } = \frac{y*y }{y(y+5) } = \frac{y}{y+5}$

г) $\frac{a^{2}-10a+25 }{a-5} = \frac{(a-5)^{2} }{(a-5)} = \frac{(a-5)}{1} = a-5$

д) $\frac{y^{2}+8y+16 }{y^{2}-16 } = \frac{(y+4)^{2} }{(y-4)(y+4)} = \frac{(y+4)(y+4)}{(y-4)(y+4)} = \frac{y+4}{y-4}$

е) $\frac{xy-49y^{2} }{x^{2}-49xy } = \frac{y(x-49y)}{x(x-49y)}=\frac{y}{x}$