Ответ:
(-∞;-5)
Объяснение:
5x-(2x-1)}} \right. \\\left \{ {{3x+3-x+2-x<0} \atop {2-5x+2x-1>0}} \right. \\\left \{ {{x+5<0} \atop {-3x>-1}} \right. \\\left \{ {{x<-5} \atop {x<\frac{1}{3} }} \right. \\ =>x<-5" alt="\left \{ {{3(x+1)-(x-2)<x } \atop {2>5x-(2x-1)}} \right. \\\left \{ {{3x+3-x+2-x<0} \atop {2-5x+2x-1>0}} \right. \\\left \{ {{x+5<0} \atop {-3x>-1}} \right. \\\left \{ {{x<-5} \atop {x<\frac{1}{3} }} \right. \\ =>x<-5" align="absmiddle" class="latex-formula">