Разложите на множители : (3х+4)^2-9х^2+16
(3х+4)^2-9х^2+16 = (3x+4)^2 + (4-3x)(4+3x) = (4+3x)^2 + (4-3x)(4+3x)= = (4+3x)(4+3x+4-3x)=8*(4+3x) 2 способ: (3х+4)^2-9х^2+16 =9x^2+24x+16-9x^2+16 = 24x+32=8(3x+4)
Решите задачу: