![1)\; \; \dfrac{x^2\, (6-x)}{x^2-4x+4}\leq 0\; \; \; \to \; \; \; \dfrac{x^2(x-6)}{(x-2)^2}\geq 0\\\\\\x_1=0\; ,\; x_2=6\; ,\; x_3=2\\\\znaki:\; \; \; ---[\, 0\, ]---(\, 2\, )---[\, 6\, ]+++\\\\\underline {\; x\in \{0\}\cup [\, 6;+\infty )\; }](https://tex.z-dn.net/?f=1%29%5C%3B%20%5C%3B%20%5Cdfrac%7Bx%5E2%5C%2C%20%286-x%29%7D%7Bx%5E2-4x%2B4%7D%5Cleq%200%5C%3B%20%5C%3B%20%5C%3B%20%5Cto%20%5C%3B%20%5C%3B%20%5C%3B%20%5Cdfrac%7Bx%5E2%28x-6%29%7D%7B%28x-2%29%5E2%7D%5Cgeq%200%5C%5C%5C%5C%5C%5Cx_1%3D0%5C%3B%20%2C%5C%3B%20x_2%3D6%5C%3B%20%2C%5C%3B%20x_3%3D2%5C%5C%5C%5Cznaki%3A%5C%3B%20%5C%3B%20%5C%3B%20---%5B%5C%2C%200%5C%2C%20%5D---%28%5C%2C%202%5C%2C%20%29---%5B%5C%2C%206%5C%2C%20%5D%2B%2B%2B%5C%5C%5C%5C%5Cunderline%20%7B%5C%3B%20x%5Cin%20%5C%7B0%5C%7D%5Ccup%20%5B%5C%2C%206%3B%2B%5Cinfty%20%29%5C%3B%20%7D "1)\; \; \dfrac{x^2\, (6-x)}{x^2-4x+4}\leq 0\; \; \; \to \; \; \; \dfrac{x^2(x-6)}{(x-2)^2}\geq 0\\\\\\x_1=0\; ,\; x_2=6\; ,\; x_3=2\\\\znaki:\; \; \; ---[\, 0\, ]---(\, 2\, )---[\, 6\, ]+++\\\\\underline {\; x\in \{0\}\cup [\, 6;+\infty )\; }")
0\end{array}\right\; \; \left\{\begin{array}{l}9\geq 3x\\(x-9)(x+7)>0\end{array}\right\; \; \left\{\begin{array}{l}x\leq 3\\x\in (-\infty ;-7)\cup (9;+\infty )\end{array}\right\\\\\\\underline {\; x\in (-\infty ;-7\, )\; }\; \; \; -\; otvet\\\\\star \; \; x^2-2x-63>0\; \; ,\; \; D/4=1+63=64\; ,\; x_1=-7\; ,\; x_2=9\; \; \; \to\\\\x^2-2x-63=(x-9)(x+7)>0\\\\znaki:\; \; +++(-7)---(9)+++" alt="2)\; \; \left\{\begin{array}{l}7-2x\geq x-2\\x^2-2x-63>0\end{array}\right\; \; \left\{\begin{array}{l}9\geq 3x\\(x-9)(x+7)>0\end{array}\right\; \; \left\{\begin{array}{l}x\leq 3\\x\in (-\infty ;-7)\cup (9;+\infty )\end{array}\right\\\\\\\underline {\; x\in (-\infty ;-7\, )\; }\; \; \; -\; otvet\\\\\star \; \; x^2-2x-63>0\; \; ,\; \; D/4=1+63=64\; ,\; x_1=-7\; ,\; x_2=9\; \; \; \to\\\\x^2-2x-63=(x-9)(x+7)>0\\\\znaki:\; \; +++(-7)---(9)+++" align="absmiddle" class="latex-formula">