Решите уравнение 1+3(5x-7)=9+11

1 способ:
1+3(5х-7)=9+11
3(5х-7)=9+11-1
3(5х-7)=19
5х-7= $\frac{19}{3}$
5х= $\frac{19}{3}+7$
5х= $\frac{19+21}{3}$
5х= $\frac{40}{3}$
х= $\frac{40}{3}:5$
х= $\frac{40}{3}* \frac{1}{5}$
х= $\frac{8}{3}$
х= $2 \frac{2}{3}$

2 способ:
1+3(5х-7)=9+11
1+15х-21=20
15х=20+21-1
15х=40
х= $\frac{40}{15}$
х= $\frac{8}{3}$
х= $2 \frac{2}{3}$