2х-0,5у-1,4=0, -2х +0.5у-0,6=0

Question

2х-0,5у-1,4=0, -2х +0.5у-0,6=0

Answer 1

(^2-это степень)1) 2x^2-0,5y-1,4=0

D=-0,5^2-4*2*(-1,4)=10.95

x1=0,5+√10.95/2=5,725

x2=0.5-√10.95/2=-5,225