РЕШИТЕ ПЖ СРОЧНО!!!!!!!!!!!!!!

$\frac{ {a}^{ - 3} \times {( {a}^{ - 2} })^{4} }{ {a}^{ - 9} } = \frac{ {a}^{ - 3 + ( - 2 \times 4)} }{ {a}^{ - 9} } = \frac{ {a}^{ - 11} }{ {a}^{ - 9} } = {a}^{ - 11 - ( - 9)} = {a}^{ - 2}$

$(\frac{ {a}^{3} }{ {b}^{2} } )^{ - 2} \times {a}^{7} {b}^{ - 3} = \frac{ {b}^{4} }{ {a}^{6} } \times {a}^{7} {b}^{ - 3} = ab$

Готово)

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