[tex]\Big(2\frac{1}{2}:10+10:2\frac{1}{2}-2\frac{1}{6}\Big)\cdot \frac{36}{125}=\\\\\\=\Big(\dfrac{5}{2\cdot 10}+\dfrac{10\cdot 2}{5}-\dfrac{13}{6}\Big)\cdot \dfrac{36}{125}=\Big(\dfrac{1}{4}+4-\dfrac{13}{6}\Big)\cdot \dfrac{36}{125}=\\\\\\=\dfrac{3+12\cdot 4-2\cdot 13}{12}\cdot \dfrac{36}{125}=\dfrac{25\, \cdot 36}{12\, \cdot 125}=\dfrac{1\cdot 3}{1\cdot 5}=\dfrac{3}{5}=0,6[/tex]