10- 2 (30+5) = 4(x-2)
где здесь х (30+5) ?
[tex]10 - 2 \times (30 + 5) = 4 \times (x - 2) \\ 10 - 2 \times 35 = 4x - 8 \\ 10 - 70 = 4x - 8 \\ - 60 = 4x - 8 \\ - 4x = - 8 + 60 \\ - 4x = 52 \\ x = 52 \div ( - 4) \\ x = - 13[/tex]