Умаляю отдаю всё прошу

Ответ:

$\left \{ {{3x+y=4} \atop {5x-2=14}} \right. \left \{ {{y=4-3x} \atop {5x-2(4-3x)=14 }} \right. \left \{ {{x=2} \atop {y= 4 - 3*2}} \right. \left \{ {{x=2} \atop {y=-2}} \right. \\\\\left \{ {{2x + 7y = 11 } \atop {4x-y=7}} \right. \left \{ {{y = 4x-7 } \atop {2x+7(4x-7)=11}} \right. \left \{ {{x=2} \atop {y=4*2-7}} \right. \left \{ {{x=2} \atop {y=1}} \right.$

Пошаговое объяснение: