Объяснение:
1)y' = 8x^7
2)y' = 0
3)y = 10 × x^-1
y' = - 10×x^-2
4)y' = 10
5)y' = 3cosx - 2× 1/2√ x = 3cosx - 1/√ x
6)y' = (3x-2)'×sinx + (3x-2)×sinx' = 3sinx + (3x-2)cosx
7)y' =2x'×sinx - 2x×sinx'\sinx^2 = 2sinx-2xcosx/sinx^2
8)y'= 8(7x+3)^7 × (7x+3)' = 8(7x+3)^7 × 7 = 56(7x+3)^7