Ответ:
Объяснение:
![\left[\begin{array}{ccc}2&-4&-2\\3&1&-1\\1&0&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%26-4%26-2%5C%5C3%261%26-1%5C%5C1%260%261%5Cend%7Barray%7D%5Cright%5D "\left[\begin{array}{ccc}2&-4&-2\\3&1&-1\\1&0&1\end{array}\right]")
Для удобства вычислений поменяем строки местами:
![\left[\begin{array}{ccc}3&1&1\\2&-4&-2\\1&0&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%261%261%5C%5C2%26-4%26-2%5C%5C1%260%261%5Cend%7Barray%7D%5Cright%5D "\left[\begin{array}{ccc}3&1&1\\2&-4&-2\\1&0&1\end{array}\right]")
Работаем со столбцом №1
Умножим 2-ю строку на (k = -1 / 2 = -1/2) и добавим к 3-й:
![\left[\begin{array}{ccc}3&1&1\\2&-4&-2\\0&2&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%261%261%5C%5C2%26-4%26-2%5C%5C0%262%262%5Cend%7Barray%7D%5Cright%5D "\left[\begin{array}{ccc}3&1&1\\2&-4&-2\\0&2&2\end{array}\right]")
Умножим 1-ю строку на (k = -2 / 3 = -2/3) и добавим к 2-й:
![\left[\begin{array}{ccc}3&1&1\\0&-14/3&-4/3\\0&2&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%261%261%5C%5C0%26-14%2F3%26-4%2F3%5C%5C0%262%262%5Cend%7Barray%7D%5Cright%5D "\left[\begin{array}{ccc}3&1&1\\0&-14/3&-4/3\\0&2&2\end{array}\right]")
Работаем со столбцом №2
Умножим 2-ю строку на (k = 2 / 14/3 = 3/7) и добавим к 3-й:
![\left[\begin{array}{ccc}3&1&1\\0&-14/3&-4/3\\0&0&10/7\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%261%261%5C%5C0%26-14%2F3%26-4%2F3%5C%5C0%260%2610%2F7%5Cend%7Barray%7D%5Cright%5D "\left[\begin{array}{ccc}3&1&1\\0&-14/3&-4/3\\0&0&10/7\end{array}\right]")