Ответ:
а.)(x-3)*(x-4)>0
0" alt="x^{2} -4x-3x+12>0" align="absmiddle" class="latex-formula">
0\\D=(-7)^{2} -4*12=49-48=1\\x_{1}=\frac{7+1}{2}=4\\x_{2}=\frac{7-1}{2}=3\\" alt="x^{2} -7x+12>0\\D=(-7)^{2} -4*12=49-48=1\\x_{1}=\frac{7+1}{2}=4\\x_{2}=\frac{7-1}{2}=3\\" align="absmiddle" class="latex-formula">
x∪[3;4]
б.)(x-3)*(x-4)<0</p>
x∪[-∞;3];[4;∞]