x*3^(x - 1) + 3*3^√(3 - x) = 3^x + x*3^√(3 - x)
одз 3 - x >= 0 x<=3</p>
x*3^(x - 1) + 3*3^√(3 - x) = 3^3^(x-1) + x*3^√(3 - x)
x*3^(x - 1) - 3^3^(x-1)= x*3^√(3 - x) - 3*3^√(3 - x)
3^(x - 1)(x - 3) = 3^√(3 - x)(x - 3)
3^(x - 1)(x - 3) - 3^√(3 - x)(x - 3) = 0
(x - 3)(3^(x - 1) - 3^√(3 - x)) = 0
1. x = 3
2. 3^(x - 1) = 3^√(3 - x)
(x - 1) = √(3 - x)
(x - 1)² = (3 - x)
x² - 2x + 1 = 3 - x
x² -x -2 = 0
D = 1 + 8 = 3
x12 = (1 +- 3)/2 = -1 2
ответ -1,2,3