БэйсикПаскаль
a = 3 + 8*4
b = (a \ 10) + 14
a = (b MOD 10) + 2
c = a + b;
a := 3 + 8*4;
b := (a div 10) + 14;
a := (b mod 10) + 2;
c := a + b;
Си++Алгоритмический язык
a = 3 + 8*4;
b = (a / 10) + 14;
a = (b % 10) + 2;
c = a + b;
a := 3 + 8*4
b := div(a, 10) + 14
a := mod(b, 10) + 2
c := a + b
Python
a = 3 + 8*4
b = (a // 10) + 14
a = (b % 10) + 2
c = a + b
