1) -x=√x, 2) x²-2x-3=0, 3) 10x²=7x-1

Question

1) -x=√x, 2) x²-2x-3=0, 3) 10x²=7x-1

Answer 1

Объяснение:

1. решений нет или же 0

2. D=b²-4ac=2²-4*1*(-3)=4+12=16=4²

x1=2-4/2=-1

x2=2+4/2=3

3.10x²-7x+1=0

D=b²-4ac=7²-4*10*1=49-40=9=3²

x1=7-9/20=-0,1

x2=7+9/20=4/5

Answer 2

Ответ:

1)

x = -

+x = 0

x(x+1) = 0

x = 0 или х+1 = 0

                х = -1.

х = 0; 1

2.

-3x+x-3 = 0

x(x-3)+(x-3) = 0

(x+1)(x-3) = 0

x+1 = 0          x-3 = 0

x = -1             x = 3

x = -1; 3

3.

10-7x+1 = 0

10-2x-5x+1 = 0

2x(5x-1)-(5x-1) = 0

(5x-1)(2x-1) = 0

5x-1 = 0         2x-1 = 0

5x = 1            2x = 1

x = 1/5           x = 1/2