Помогите решить ДАМ 25 БАЛЛОВ ПРОШУ ВАС ПОМОГИТЕ ДАМ 25 БАЛЛОВ ПРОШУ ВАС ПОМОГИТЕ!!!!!!!!!

Ответ:

$1\frac{1}{3}*(8\frac{2}{3}:1\frac{4}{9}-3\frac{3}{8}+1\frac{5}{8})-1\frac{5}{6}=\frac{4}{3}*(\frac{26*9}{3*13}-1\frac{6}{8})-1\frac{5}{6}=\frac{4}{3}*(6-1\frac{3}{4})-1\frac{5}{6}=\frac{4}{3}*4\frac{1}{4}-1\frac{5}{6}=\frac{4*17}{3*4}-1\frac{5}{6}=5\frac{2}{3}-1\frac{5}{6}=5\frac{4}{6}-1\frac{5}{6}=3\frac{5}{6}$

$(3\frac{1}{15}-1\frac{1}{15}:1\frac{3}{5}+\frac{2}{5})*2\frac{1}{7}-1\frac{1}{7}=(3\frac{1}{15}-\frac{16*5}{15*8}+\frac{6}{15})*\frac{15}{7}-1\frac{1}{7}=(3\frac{7}{15}-\frac{2}{3})*\frac{15}{7}-1\frac{1}{7}=(3\frac{7}{15}-\frac{10}{15})*\frac{15}{7}-1\frac{1}{7}=\frac{42*15}{15*7}-1\frac{1}{7}=6-1\frac{1}{7}=4\frac{6}{7}$

$19,6*2\frac{1}{3}-(2,0625 - 1\frac{5}{12}):\frac{1}{8}=\frac{196*7}{10*3}-(2\frac{1}{16}-1\frac{5}{12})*8=\frac{1372}{30}-(2\frac{3}{48}-1\frac{20}{48})*8=45\frac{22}{30}-\frac{31}{48}*8=45\frac{11}{15}-\frac{31}{6}=45\frac{22}{30}-5\frac{5}{30}=40\frac{17}{30}$

$\frac{5}{16}:0,125+1,456: \frac{7}{25}+4,5*\frac{4}{5}=\frac{5*8}{16}+\frac{1456*25}{1000*7}+\frac{45*4}{10*5}=2,5 +5,2+3,6=11,3$

Пошаговое объяснение: