Ответ:
[-1.5; 4.5)
Пошаговое объяснение:
0;}} \right. \\\left \{ {{2x\ge-3,} \atop {2x" alt="f(x)=\sqrt{2x+3}-\frac{1}{\sqrt{9-2x}}\\D(f):\\\left \{ {{2x+3\ge0,} \atop {9-2x>0;}} \right. \\\left \{ {{2x\ge-3,} \atop {2x" align="absmiddle" class="latex-formula">