Ответ:
4-x=6^{2}=>4-x=36=> x=4-36 => x=-32" alt="\sqrt{4-x} =6 => 4-x=6^{2}=>4-x=36=> x=4-36 => x=-32" align="absmiddle" class="latex-formula">
(\frac{1}{25}) ^{x-2} =(\frac{1}{25}) ^{-\frac{1}{2} } =>x-2=-\frac{1}{2}=>x-2=-0,5=>x=2+0,5=>x=2,5" alt="(\frac{1}{25}) ^{x-2}= 5=>(\frac{1}{25}) ^{x-2} =(\frac{1}{25}) ^{-\frac{1}{2} } =>x-2=-\frac{1}{2}=>x-2=-0,5=>x=2+0,5=>x=2,5" align="absmiddle" class="latex-formula">
(\frac{1}{25}) ^{x-2} x-2>-\frac{1}{2}=>x-2>-0,5=>x>2+0,5=>x>2,5" alt="(\frac{1}{25}) ^{x-2}< 5=>(\frac{1}{25}) ^{x-2} x-2>-\frac{1}{2}=>x-2>-0,5=>x>2+0,5=>x>2,5" align="absmiddle" class="latex-formula">
Ответ: x∈(2,5;+∞)
Объяснение: