Ответ:
0 \\ 5x - 15 > 0 \\ 5x > 15 \\ x > 3 \\ x > - 6 \\ x > 8 \\ " alt="(5x - 15) \div ((x + 6)(x - 8)) > 0 \\ 5x - 15 > 0 \\ 5x > 15 \\ x > 3 \\ x > - 6 \\ x > 8 \\ " align="absmiddle" class="latex-formula">
интервалға саламыз
—{-6}+{3}—{8}+ 0ден үлкен
яғни,
х=(-6;3)U(8;inf)