Log1/3(4x+1)=-3 please​

Question

Log1/3(4x+1)=-3 please​

Answer 1

-\frac{1}{4}\\log_{\frac{1}{3}}(4x+1)=log_{\frac{1}{3}}27\\4x-1=27\\4x=28\\x=7" alt="log_{\frac{1}{3}}(4x+1)=-3\\ODZ:x>-\frac{1}{4}\\log_{\frac{1}{3}}(4x+1)=log_{\frac{1}{3}}27\\4x-1=27\\4x=28\\x=7" align="absmiddle" class="latex-formula">Ответ:

Пошаговое объяснение: