Решите пж, 7 класс внизу срочно спасибо заранее

Ответ:

$(-x^2y^2)^4\cdot (-xy)^2=x^8y^8\cdot x^2y^2=x^{10}y^{10}\\\\-\Big(\dfrac{1}{3}xy^3\Big)^2\cdot (-3x)^3=-\dfrac{x^2y^6}{9}\cdot (-27x^3)=3x^5y^6\\\\\\(-2x^3y^2)^3\cdot (-2y^2)^3=-8x^9y^6\cdot (-8y^6)=64x^9y^{12}\\\\\\\Big(\dfrac{1}{3}a^2b\Big)^3\cdot (9ab^2)^2=\dfrac{1}{27}a^6b^3\cdot 81a^2b^4=3a^8b^7\\\\\\ (-5a^3b)^2\cdot \Big(\dfrac{1}{5}ab^3\Big)^3=25a^6b^2\cdot \dfrac{1}{125}a^3b^9=\dfrac{a^9b^{11}}{5}$

$\Big(-\dfrac{2}{7}ab^4\Big)^2\cdot \Big(-3\dfrac{1}{2}a^3b\Big)^2=\dfrac{4}{49}\, a^2b^8\cdot \dfrac{49}{4}\, a^6b^2=a^8b^{10}$

$(x^3y^2)^2\cdot (-5xy)^3=x^6y^4\cdot (-125x^3y^3)=-125x^9y^7\\\\\\\Big(\dfrac{1}{6}x^2y^2\Big)^2\cdot (-12x^3y^5\Big)^2=\dfrac{1}{36}\, x^4y^4\cdot 144\, x^6y^{10}=4x^{10}y^{14}$