1-a(a-b+c)+b(a-b+c)+c(b-a-c) разложить ** множетили​

Question

1-a(a-b+c)+b(a-b+c)+c(b-a-c) разложить на множетили​

Comments

дальше устно

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(a-b+c)(-a+b-c)

Answer 1

1–a(a–b+c)+b(a–b+c)+c(b–a–c)=

= 1–а(а–b+c)+b(a–b+c)–c(a–b+c)=

=1–(a–b+c)(a–b+c)=

=1–(a–b+c)²= (1–a+b–c)(1+a–b+c).