1 => x \in \varnothing\\10.\\\frac{17}{3}\pi = (4 + \frac{5}{3})\pi = 4\pi + \frac{5}{3}\pi = 4\pi + \pi + \frac{2}{3}\pi = 4\pi + \pi + \frac{\pi}{2} + \frac{\pi}{6} \in IV\\" alt="6.\\tan(7x+11) = 43\\7x + 11 = atan43 + \pi n, n \in Z\\x = \frac{1}{7}(atan43 - 11) + \frac{\pi}{7} n, n \in Z\\7.\\2\sqrt{2}cos(x^8 + x^7 + 1) =3\\cos(x^8 + x^7 + 1) = \frac{3}{2\sqrt{2}} > 1 => x \in \varnothing\\10.\\\frac{17}{3}\pi = (4 + \frac{5}{3})\pi = 4\pi + \frac{5}{3}\pi = 4\pi + \pi + \frac{2}{3}\pi = 4\pi + \pi + \frac{\pi}{2} + \frac{\pi}{6} \in IV\\" align="absmiddle" class="latex-formula">
Очевидно, что √11 > √9 = 3. Сравним его с 
:
Так как 49 > 44, то 
\sqrt{11} => 3\pi " alt="\frac{7}{2} > \sqrt{11} => 3\pi " align="absmiddle" class="latex-formula">
