1) 2y^2=1 2)-x^2-6x=1 3)2x+x^2-1=0

Question

1) 2y^2=1 2)-x^2-6x=1 3)2x+x^2-1=0

Answer 1

Ответ:

1)2y^2=1;

4y=1;

y=0.25

2)-x^2-6x=1;

-4x=1;

x=-0.25;

3)2x+2^x-1=0;

4x-1=0;

4x=1;

x=0.25