1) 5(x-1)+7<1-3x+3=
5(x-1)+7<1-3x+3</strong>
5x -5 + 7 < 1 - 3x + 3
5x + 3x < 1 + 3 + 5 - 7
8x < 2
x < 0.25
Ответ: x∈(-∞;0.25)