m(K3PO4) = 53 g M(K3PO4) = 39 * 3 + 31 + 16*4 = 117 + 31 + 64 = 212
m(KOH) - ? N(K3PO4) = 53/212 = 0.25 моль
m(H3PO4) - ? m = M * N
x моль 0.25 моль
3KOH + H3PO4 → K3PO4 + 3H2O
3 моль 1 моль
3:x = 1:0.25
0.75 = 1x
x = 0.75
N(KOH) = 0.75 моль
m(KOH) = 0.75 * ( 39 + 1 + 16) = 0.75 * 56 = 42 g
x моль 0.25 моль
3KOH + H3PO4 → K3PO4 + 3H2O
1моль 1 моль
1:x = 1:0.25
x = 4 N(H3PO4) = 4
m(H3PO4) = 4 * (16*4 + 31 + 1*3 ) = 4 * 98 = 392g
Ответ: m(KOH) = 42g, m(H3PO4) =392g