Ответ:
1) х²-4х-32 = (х - 8)(х+ 4); 2)4х²-15х+9 = 4(х- 3)(х - 3/4)
Объяснение:
1) х²-4х-32 = (х - 8)(х+ 4)
х²-4х-32 = 0
х1 + х2 = 4; х1= - 4
х1· х2 = - 32; х2= 8
2)4х²-15х+9 = 4(х- 3)(х - 3/4)
4х²-15х+9 =0
Д= (-15)² - 4· 4· 9 = 225 - 144 = 81
х1 = 15 + 9/2· 4 = 24/8 = 3
х2 = 15 - 9/2 · 4 = 6/8 = 3/4