Ответ:
FeCL3+3NaOH-->Fe(OH)3+3NaCL
2Fe(OH)3-->Fe2O3+3H2O
Fe2O3+6HNO3-->2Fe(NO3)3+3H2O
Fe2O3+3H2-->2Fe+3H2O
Fe+2HCL-->FeCL2+H2
FeCL2+2NaOH-->Fe(OH)2+2NaCL
дано
m(HCL) = 365
-----------------------
n(NaCL) - ?
HCL+NaOH-->NaCL+H2O
M(HCL) = 36.5 g/mol
n(HCL) = m(HCL) / M(HCL) = 365 / 36.5 = 10 mol
n(HCL) = n(NaCL) = 10 mol
n(NaCL) = 10 mol
M(NaCL) = 58.5 g/mol
m(NaCL) = n(NaCL) * M(NaCL) = 10 * 58.5 = 585 g
ответ 10 моль , 585 г
Объяснение: