6х*0,3+4*(1,3х+20у) при х=1, у=0,1

Question

6х*0,3+4*(1,3х+20у) при х=1, у=0,1

Answer 1

6х*0,3+4*(1,3х+20у)=1,8х+5,2х+80у=7х+80у

при х=1, у=0,1            7*1+80*0,1=7+8=15

Answer 2

6x * 0,3 + 4 * (1,3x + 20y) = 1.8x + 5.2x + 80y = 7x + 80y

 

7*1 + 80 * 0.1 = 7 + 8 = 15