6^x-4*3^x-2^x+4<=0 <br> (3*2)^x - 4*3^x - 2^x + 4 = 0 3^x * 2^x - 4*3^x - 2^x + 4 = 0 3^x * (2^x - 4) - (2^x - 4) = 0 (3^x - 1) * (2^x - 4) = 0 1) 3^x - 1 = 0 => 3^x=1 => x=0 2) 2^x - 4 = 0 => 2^x=4 => 2^x=2^2 => x=2 Ответ: х=0 и х=2