(5y+1)² = (4z-3)² = (3a+2)² = (4-2b)² = (3+6c)² = (1-2k)² = (5+3t)² =

Question

(5y+1)² =

(4z-3)² =

(3a+2)² =

(4-2b)² =

(3+6c)² =

(1-2k)² =

(5+3t)² =

Answer 1

(5y+1)² =25у²+10у+1

(4z-3)² =16z²-24z+9

(3a+2)² =9а²+12а+4

(4-2b)² =16-16b+4b²

(3+6c)² =9+36с+36с²

(1-2k)² =1-4k+4k²

(5+3t)² =25+30t+9t²

 

(5y+1)² = (4z-3)²

25у²+10у+1=16z²-24z+9

 

Answer 2

(5y+1)² =25у²+10у+1

(4z-3)² = 16z²-24z+9

(3a+2)² = 9a²+12a+4

(4-2b)²=-(2b-4)²=-(4b²-16b+16)=-4b²+16b-16=4b²-16b+16

(3+6c)²=(6c+3)²=36c²+36c+9

(1-2k)²=-(2k+1)²=-(4k²+4k+1)=-4k²-4k-1=4k²+4k+1

(5+3t)²=(3t+5)²=9t²+30t+25