\frac{3}{9} > \frac{2}{9} ;
\frac{7}{8} >\frac{5}{8} > \frac{2}{8} ;
\frac{4}{7} > \frac{1}{7} ;
\frac{5}{6} = \frac{10}{12} > \frac{2}{3}
" alt=" \frac{5}{9} >\frac{3}{9} > \frac{2}{9} ;
\frac{7}{8} >\frac{5}{8} > \frac{2}{8} ;
\frac{4}{7} > \frac{1}{7} ;
\frac{5}{6} = \frac{10}{12} > \frac{2}{3}
" align="absmiddle" class="latex-formula">
осталась 1 дробь
\frac{3}{15} " alt=" \frac{7}{15} > \frac{3}{15} " align="absmiddle" class="latex-formula">