1) (х+7)(2х-5)= 02) х(2х-3)(х-6)= 0

Question

1) (х+7)(2х-5)= 0
2) х(2х-3)(х-6)= 0

Comments

x(2x^2-12x-3x+18)=0;

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x(2x-3)(x-6)=0;

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X1,2=-9+/-19/4; x=-7, x=2,5

Answer 1

(x+7)(2x-5)=0;
2x^2-5x+7x-35=0;
2x^2+2x-35=0;
a=2 b=2 c=-35
D=4+140=144;
x1=2,5
x2=-3,5

Answer 2

(х+7)(2х-5)=2х^2+9х-35
х1=10/4=2.5
х2=28/4=7

Comments

х (2х-3)(х-6)=(2х^3-15х^2+18х)/х=2х^2-15х+18.

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D=225-144=81=9. х1=24/4=6. х2=6/4=3/2=1.5