\infty} \frac{x^3+x^2}{3-x^2}=\\\\lim_{x->\infty} \frac{1+\frac{1}{x}}{\frac{3}{x^3}-\frac{1}{x}}=|\frac{1}{0}|=\infty" alt="lim_{x->\infty} \frac{x^3+x^2}{3-x^2}=\\\\lim_{x->\infty} \frac{1+\frac{1}{x}}{\frac{3}{x^3}-\frac{1}{x}}=|\frac{1}{0}|=\infty" align="absmiddle" class="latex-formula">