Решите неравенство 5(4y+3) - 7 (3y-4)≤ 10 2(z-2)/9≤ 3+z/712-y< 5(y-1)/6

Question

Решите неравенство
5(4y+3) - 7 (3y-4)≤ 10
2(z-2)/9≤ 3+z/7
12-y< 5(y-1)/6

Answer 1

20у+15-21у+28<=10<br>-y+43<=10<br>-y<=10-43<br>-y<=-33<br>y=>33
Ответ (-бесконечности; 33]
7*2(z-2)<=9(3+Z)<br>14z-28<=27+9z<br>14z-9z<=27+28<br>5z<=55<br>z<=55/5<br>z<=11<br>[11;+ бесконечности)
6*(12-y)<5(y-1)<br>72-6y<5y-5<br>-6y-5y<-5-72<br>-11y<-77<br>y>-77/-11
y>7
(-бесконечности,7)