найти корни уравнения8х^2+10х-3=0

Question

найти корни уравнения
8х^2+10х-3=0

Answer 1

8x2 + 10x - 3 = 0
D = b2 - 4ac
D = 100 + 96 = 196 = 14^2

x1,2 = -b ± √D/2a
x1 = -10 + 14/16 = 4/16 = 1/4=0.25
x2 = -10 - 14/16 = - 24/16 = - 3/2=-1.5
Ответ: x1 = 0.25 ; x2 = -1.5

Answer 2

d=100+96=196

x1=(-10+14)/16=0.25

x2=(-10-14)/16=-1.5