Помогите!14b+(b+7)(b-7)+(b-7)^2при b= -1/3

Question

Помогите!
14b+(b+7)(b-7)+(b-7)^2
при b= -1/3

Answer 1

14b+(b-7)(b+7+b-7)=14b+2b(b-7)=14b+2b^2-14b=2b^2.
2*(-1/3)^2=2*1\9=2\9