МОЛЮ С ЧЕРТЕЖОМ !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Решите задачу:

$f(x)=ax^2+bx+c \\\ m=- \frac{b}{2a} \\\ n=f(m) \\\ A(m;n) \\\ x=m$

$f(x)=-(x+1)^2+3 \\\ A_1(-1;3) \\\ x=-1$

$f(x)=2x^2-2x-4 \\\ m=- \frac{-2}{4}=0.5 \\\ n=f(0.5)=2\cdot0.5^2-2\cdot0.5-4=-4.5 \\\ A_2(0.5;-4.5) \\\ x=0.5$

$f(x)=x(1-x)=x-x^2 \\\ m=- \frac{1}{-2}=0.5 \\\ n=f(0.5)=0.5(1-0.5)=0.25 \\\ A_3(0.5;0.25) \\\ x=0.5$